Answer:
![\displaystyle [7x + 2][3x - 7]](https://img.qammunity.org/qa-images/2023/formulas/mathematics/high-school/ivdq83pr878vaauq0tqk.png)
Explanation:
Find two quantities that when differed to 43, they also multiply to 294. Those will be 6 and 49. The TINIER quantity gets the plus symbol because the B-value is −43, therefore 49 gets the minus symbol, leaving 6 with the plus symbol. In extension, sinse we have a leading coefficient greater than one, we need to take extra procedures. Here is how it is done:
![\displaystyle 21x^2 - 43x - 14 \\ \\ [21x^2 + 6x] - [49x - 14] \\ 3x[7x + 2] - 7[7x + 2] \\ \\ \boxed{[7x + 2][3x - 7]}]()
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