Question

A box contains:

3 red crayons
7 blue crayons
4 yellow crayons
8 green crayons
2 black crayons
1 orange crayon
A crayon is chosen at random and replaced 50 times. What is a reasonable prediction for the number of times a blue or orange crayon will be drawn?

Answer 1

16 times

Explanation:

We first have to find the total amount of crayons:

`3+7+4+8+2+1=25`

That means that the box contains a total of 25 crayons. Of those 25 crayons, 7 are blue and 1 is orange. That means every time one crayon is chosen from the box, there is an 8 in 25 chance it will be blue or orange. We can represent that chance as a fraction:
`(8)/(25)`

That
`(8)/(25)` chance occurs each time ONE crayon is chosen, so if we want to know how many times blue or orange will be chosen after 50 times, we can multiply that chance by 50.

`(8)/(25)*50=400/25`

Then you simplify the fraction:

`(400)/(25)=16`

That means that if you pull crayons from the box 50 times, a blue or orange crayon will be likely drawn around 16 times.