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What is the equation that is perpendicular to the line y=2x-3 and passes through the point (-6,5)? Show all of your work.

y = -2x - 7
y = 2x + 17
y = 1/2x + 8
y = -1/2x + 2

User Christie
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1 Answer

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Answer:

y = m x + b equation for a straight line

m m' = -1 for perpendicular lines

Thus m' = -1/2 is required

Check:

-1/2 * -6 + 2 = = 3 + 2 = 5 = y for the last equation give

User XGeo
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