Question

Plss help!
Question: Find a,b and c​

Answer 1

See below, please

Explanation:

The right：

`{(y + c)}^(2) - b * (x + a) \\ = ( {y}^(2) + 2yc + {c}^(2) ) - bx - ba =`

`= {y}^(2) - bx + 2cy + {c}^(2) - ab`

The left:

`= {y}^(2) - 7x - 18y + 109`

So, after comparing the right side and the left side of this equation, we know

1)

`b = 7`

2)

`2c = - 18 \\ so \\ c = - 9`

3)

`{c}^(2) - ab = 109`

So,

`a = \frac{ {c}^(2) - 109}{b} = \frac{ { (- 9)}^(2) - 109}{7} = ( - 28)/(7) = - 4`