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2cosAcosB = • cos(A + B) + cos(A - B) • sin(A - B) + tan(A + B)
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5 votes
2cosAcosB =

• cos(A + B) + cos(A - B)
• sin(A - B) + tan(A + B)

User Bilal Shah
by
5.7k points

1 Answer

6 votes

Answer:

2cosAcosB = cos( A + B ) + cos( A - B )

User Dark Cyber
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