Question

Can someone help me!

Answer 1

Step-by-step explanation:

For example 1, there is no friction, so the acceleration in example 1 is:
`\sum F=F=100=ma \rightarrow a=(100)/(50)=2 ms^(-2)`

For example 2, there is a friction, so the acceleration in example 2 is:

`\sum F=F-f=100-40 = 60 = ma\rightarrow a_(2)=(60)/(50)=1.2 ms^(-2)`

Here we can say that "according to Newton's 2nd Law, the box in example 2 has less acceleration than in the example 1". So, the claim is denied.