Question

Solve for x in the equation x ^ 2 + 2x + 1 = 17

O x = - 1 plus/minus sqrt(13)

O x = - 2 plus/minus 2 * sqrt(5)

O x = - 1 plus/minus sqrt(17)

O x = - 1 plus/minus sqrt(15)

Answer 1

Answer:C

Explanation:

Answer 2

`x=-1+√(17),\:x=-1-√(17)`

Explanation:

`x ^ 2 + 2x + 1 = 17`

`\mathrm{Subtract\:}17\mathrm{\:from\:both\:sides}`

`x^2+2x+1-17=17-17`

`\mathrm{Simplify}`

`x^2+2x-16=0`

`\mathrm{Solve\;with\;Quadratic\;formula}`

`x_(1,\:2)=(-2\pm √(2^2-4\cdot \:1\cdot \left(-16\right)))/(2\cdot \:1)`

`√(2^2-4 \cdot1\cdot(-16)) =\sqrt[2]{17}`

`x_(1,\:2)=(-2\pm \:2√(17))/(2\cdot \:1)`

`\mathrm{Separate\:the\:solutions}`

`x_1=(-2+2√(17))/(2\cdot \:1),\:x_2=(-2-2√(17))/(2\cdot \:1)`

`\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}`

`x=-1+√(17),\:x=-1-√(17)`

Hence, Answer is [C]
`x=-1+√(17),\:x=-1-√(17)`

~Lenvy~