Question

Rotate the point 832° to within 10°.

Answer 1

If you rotate point (px, py) around point (ox, oy) by angle theta you'll get:

p'x = cos(theta) * (px-ox) - sin(theta) * (py-oy) + ox

p'y = sin(theta) * (px-ox) + cos(theta) * (py-oy) + oy