Answer:
Explanation:
Q8:
y= -x+4 (given)
Slope of given the line=-1
For required slope which is passing through (6,5):
Using Point slope form:
![y-y_(1) = m(x-x_(1) )](https://img.qammunity.org/2022/formulas/mathematics/college/vyorfk7z4fkwpux1qedda2te1s3zj8vvrh.png)
y-5=-1(x-6) (m=-1 because lines are parallel)
y-5=-x+6
x+y-5-6=0
x+y-11=0
Q9:
y=-4x-7
slope of the given line:
m=-4
Slope of required line:
m=1/4
Using Point slope form:
![y-y_(1) = m(x-x_(1) )](https://img.qammunity.org/2022/formulas/mathematics/college/vyorfk7z4fkwpux1qedda2te1s3zj8vvrh.png)
y+1=1/4(x-8)
4y+4=x-8
x-4y-8-4=0
x-4y-12=0