Answer:
4
Explanation:
Answer:
Option 4 is correct.
Explanation:
To find: Polynomial whose solution are not real numbers.
Given Polynomials are Quadratic Polynomial.
So, we can check if solution of quadratic polynomial by find & checking value of discriminant.
Standard form of Quadratic polynomial is given by
ax² + bx + c
then Discriminant, D = b² - 4ac
If, D > 0 ⇒ Solutions are distinct real numbers
if, D = 0 ⇒ Solutions are equal real numbers
if, D < 0 ⇒ Solutions are not real numbers (They are complex conjugates)
Option A:
By comparing with standard form
a = 1 , b = -6 , c = 3
D = (-6)² - 4 × 1 × 3 = 36 - 12 = 24 > 0
Thus, Solutions are Real numbers.
Option B:
By comparing with standard form
a = 1 , b = 4 , c = 3
D = (4)² - 4 × 1 × 3 = 16 - 12 = 4 > 0
Thus, Solutions are Real numbers.
Option C:
By comparing with standard form
a = -1 , b = -9 , c =-10
D = (-9)² - 4 × (-1) × (-10) = 81 - 40 = 41 > 0
Thus, Solutions are Real numbers.
Option D:
By comparing with standard form
a = 1 , b = 2 , c = 3
D = (2)² - 4 × 1 × 3 = 4 - 12 = -8 < 0
Thus, Solutions are not Real numbers.
Therefore, Option 4 is correct.