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13) mZFCD= x +41, mZBCF= x + 78,
and mZBCD=95°. Find x.
BO
C
D

13) mZFCD= x +41, mZBCF= x + 78, and mZBCD=95°. Find x. BO C D-example-1
User Peter Smit
by
5.0k points

1 Answer

1 vote

Answer:

x = - 12

Explanation:

∠ FCD + ∠ BCF = ∠ BCD , substitute values

x + 41 + x + 78 = 95 , that is

2x + 119 = 95 ( subtract 119 from both sides )

2x = - 24 ( divide both sides by 2 )

x = - 12

User Sollniss
by
4.8k points