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I need help with this problem,

I need help with this problem,-example-1

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Answer:

JL = 78

Explanation:

The shorter segment is a midline, so is half the length of the longer one.

2(5x-16) = 4x +34

5x -16 = 2x +17 . . . . . divide by 2

3x = 33 . . . . . . . . . . add 16-2x

x = 11 . . . . . . . . . . divide by 3

Then segment JL is ...

JL = 4x +34 = 4(11) +34 = 44+34

JL = 78

User Ruud Visser
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