Question

Plzz help asap rewrite the equation to the form ax^2+bx+c=0: x^2+(1-x)(1-3x)=x

Answer 1

`4x^2 - 5x + 1 = 0`

Explanation:

`x^2+(1-x)(1-3x)=x\\x^2+(1-x)(1-3x) - x = 0\\x^2+ 3x^2 - 4x + 1 - x = 0\\\\`

4x^2 - 5x + 1 = 0