212k views
24 votes
Problem is in the image

Problem is in the image-example-1

1 Answer

7 votes

Answer:

0 < c < 1

Explanation:

Descarte's rule of signs tells you the quadratic will have two or zero positive real roots when the sign of c is positive. (c > 0)

The discriminant tells you the quadratic will have real roots when ...

b² -4ac > 0 . . . . . . where a, b, c are the coefficients of ax² +bx +c = 0

(-2)² -4(1)c > 0

1 -c > 0

c < 1

The equation will have two positive real roots when 0 < c < 1.

User BenVida
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories