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Use -b/2a to find the axis of symmetry equation and the vertex g(x) = x^2-5x

Use -b/2a to find the axis of symmetry equation and the vertex g(x) = x^2-5x-example-1
User Elham Gdz
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1 Answer

2 votes

Answer:

Axis of symmetry (-b/2a)= -2.5 or -5/2

Vertex- (2.5, -6.25) or (-5/2, -25/4)

Explanation:

Find the AOS= -(-5)/2(1)= 2.5

Find the vertex= (2.5)^2 - 5(2.5)= -6.25

User AJak
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