Question

What is an equation of the line that passes through the points (6,-3) and (-6,-5)

Answer 1

Explanation:

Bu using the formula of Two-Points form:

`(y-y_(1) )/(y_(2)-y_(1) ) =(x-x_(1) )/(x_(2)-x_(1) )`

Substitute the points in the above equation:

y+3/-5+3=x-6/-6-6

y+3/-2=x-6/-12

-12(y+3)=-2(x-6)

-12y-24=-2x+6

2x-12y-24-6=0

2x-12y-30=0

Or

x-6y-15=0

If you need to ask any question,let me know.

Answer 2

y = 6x - 4

Explanation:

I drew a graph slope formula is (y2 - y1)/(x2 - x1) and if the line passes through a point that is not zero (in this case it does) we add or subtract that as the y-intercept. we recently passed this so I know it.

Slope-intercept form: (y = mx + b) y = 6x - 4

Standard form: (Ax + By = C) -6x + y = -4

Point-slope form: (y - y1 = m (x - x1)) (let's use the point (6, -3)) y + 3 = 6 (x - 6)

Tell me if I'm wrong :)