Answer:
2, 8, 4, 16, 12, 30, 26, 50
Explanation:
The first is determinate the different (
) between each consecutive value (
).
![8 - 2 = 6\\4 - 8 = -4\\16 - 4 = 12\\12 - 16 = -4\\](https://img.qammunity.org/2022/formulas/mathematics/high-school/dqw4vxc7nukeqyjdwsi3pu0anw2nkrqbe8.png)
How you can see when the position of the number in the sequence is odd you have to sum a number
and when the position of the number in the sequence is a even number you have to substract -4.
Why
? If you see the first two odd position numbers in the sequence are multiples of 6, then we made the deduction that each time that you sum a number this is a multiply of 6 and -4 is constant for each position even number.
Then for each odd position number in the sequence it's representation is of the form:
![a_(n-1) + 6x = a_n](https://img.qammunity.org/2022/formulas/mathematics/high-school/ss09dcmk0jeqmxwgdw1xgcpjht5w4dqqnn.png)
Where
is the number of before,
the odd position of the number in the sequence and
is the current value of
![a_n](https://img.qammunity.org/2022/formulas/mathematics/college/4zpdm7q59fgrvra6pno62myrp1nfhrtfg4.png)
So the rest of the sequence is of the next form:
![12 + 6(3) = 30](https://img.qammunity.org/2022/formulas/mathematics/high-school/67vor75pzpk24q9at033bxhkpf4zgul69j.png)
![30 -4 = 26](https://img.qammunity.org/2022/formulas/mathematics/high-school/u1774mwwq24ypavcq2lsgzzouqjmqy8e75.png)
![26 + 6(4) = 50](https://img.qammunity.org/2022/formulas/mathematics/high-school/q32s02xehfkdka2id5l2o0v6mmsmpviohb.png)
So the final answer is
![\{30, 26, 50\}](https://img.qammunity.org/2022/formulas/mathematics/high-school/5nf73w7ezmfrib1sdbqhn4qdv5jrp0ismh.png)