Question

Help please!! I will mark brainilist and give a lot of points.

This is Pythagorean theorem.


Formula: a^2+b^2=c^2


When I say ^2 I mean to the power of 2.


The question is asking me to solve for a.


Then give me b and c which is b = 17 1/3 and c = 16.


How do I solve for a when b is greater than c? Won’t that give me a negative a? You can’t have a negative a right?


Unless I’m wrong.



Please help my solve this!!!!! :D

Answer 1

a = 23.588

Explanation:

a^2 = 17 1/3^2 + 16^2

a^2 = 300.4 + 256

a^2 = 556.4

a = 23.588 (I rounded to thousandths but you can round to whatever)

Answer 2

Hello there,

• I just looked into the question and you are absolutely right whatever you inferred.
• I think the question might be wrong.
• The value of c should be greater than b.
• I guess it will like this:
• 
  `b = 16 \: \: \: c = 17 (1)/(3)`
• The values should be like this.
• I am solving the equation by this:
• 
  `{a}^(2) = {c}^(2) - {b}^(2) \\ = > {a}^(2) = {(17 (1)/(3)) }^(2) - {(16)}^(2) \\ = > {a}^(2) = {( (52)/(3) )}^(2) - {(16)}^(2) \\ = > {a}^(2) = ( (52)/(3) - 16)( (52)/(3) + 16) \\ = > {a}^(2) = ( (52 - 48)/(3) )( (52 + 48)/(3) ) \\ = > {a}^(2) = (4)/(3) * (100)/(3) \\ = > {a}^(2) = (400)/(9) \\ = > a = \sqrt{ (400)/(9) } \\ = > a = (20)/(3) \\ = > a = 6 (2)/(3)`
• So, the value of a is
• 
  `a = 6 (2)/(3)`

Hope you could get an idea from it.

Doubt clarification - use comment section.