Question

What is the equation of line that passes through(-6,-3) and is parrelel to the line 5x-3y=9

Answer 1

Answer:
`(5)/(3)`x + 7

Step-by-step explanation:

Answer 2

y+3=5/3(x+6)

Explanation:

Since it is parallel to 5x-3y=9, you need to find the slope of that line because then you would find the slope to your line.

5x-3y=9

5x=9+3y

5x-9=3y

y=5/3x-3, and the slope would be 5/3.

Now you can apply point slope form
`y-y_(1)=m(x-x_(1) )` to get an equation.

y+3=5/3(x+6)