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Suppose a spherical balloon is inflated at the rate of 10 cubic centimeters per minute. How fast is the radius of the balloon increasing when the radius is 5 cm

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Answer: The radius increases by 0.032 cm/minute.

Explanation:

The volume, V, of a sphere is V = (4/3)πr^3.

For the volume to increase at a rate of 10cc (cubic centimeters) per minute, the radius must increase such that the additional radius (r)^3 = 10

V = (4/3)πr^3

V = (4/3)π5^3

V = 524 cc

We add 10 cc to have the balloon hold 544 cc. We calculate the increase in radius:

534=(4/3)*pi*x^3

We can now calculate the new radius, x.

x = 5.032 cm

The radius increased by 0.032 cm/minute.

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