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The L.C.M of two numbers is 2079 and their H.C.F. is 27. If one of the numbers is 297, then the other number is: ​

User Rika
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1 Answer

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Explanation:

2079 / 297 = 7

that is the first indication about what we need.

but 7 itself can't be the solution, because the solution needs to contain at least a factor of 27.

297 = 27×11

therefore,

2079 = 27×11×7

and the other number must now be

27×7 = 189

because due to the HCF it has to be divisible by 27, but must have another additional factor. a factor that allows it to divide 2079 without remainder, and makes it big enough to block any LCM lower than 2079.

there are only 2 other factors available in 2079 : 11 and 7.

297 has already "taken" 11, and the two numbers cannot be the same (otherwise the LCM and the HCF would be the number itself), so that leaves 7 for the other number.

hence the solution.

the other number is 189

and the other number must then be 27×7 = 189

User Agartzke
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