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When solving the following quadratic equation by completing the square, what do you do to the "b" term (or 6)? x2 + 6x - 3 = 0
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When solving the following quadratic equation by completing the square, what do you do to the "b" term (or 6)?

x2 + 6x - 3 = 0

User JBeckton
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wouldn’t you combine like terms and add it to x2 ? im not 100% sure thats right but its what first came to mind
User QBrute
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