Question

This is urgent I really I need the answers
Thanks in advance

Answer 1

equation: 2y = 3x + 15

If cross y-axis, the x will be 0

2y = 3(0) + 15

2y = 15

y = 7.5

crosses y-axis at (0, 7.5)

(b)

P(-1,10), Q(3,4)

(i) gradient:

`\sf (y_2-y_1)/(x_2-x_1)`

`\rightarrow \sf (4-10)/(3--1)`

`\rightarrow \sf (-6)/(4)`

`\rightarrow \sf -1.5`

(ii) midpoint:

`\sf (x_m, y_m) = ((x_1+x_2)/(2), (y_1+y_2)/(2))`

`\rightarrow \sf (x_m, y_m) = ((3-1)/(2), (4+10)/(2))`

`\rightarrow \sf (x_m, y_m) = (1,7)`