Question

V=VyV67.2 -8.2 m/s

Part B
Now let's see if your prediction agrees with the experimental results. There isn't any data at y=-3.5 m, so you'll need to interpolate by zooming in
on the relationship between y velocity (W) and y displacement. You'll use Tracker's Data tool to help with this analysis. Follow these steps:
• Change the vy versus t graph to a vy versus y graph. (Click the t label on the horizontal axis and select y. position y-component from the
menu.)
• It's a little hard to see what's going on with this graph at y = -3.5, so zoom in. Double-click on the graph to open it up in the Data tool.
. Put your cursor on the point where the graph line intersects y = -3.5. Click and hold to read the vy at that point shown in a yellow box in the
bottom left comer).
What's the interpolated graph value of v, at y = -3.57 Comment on how well this value agrees with the value of v, that you calculated in part A of
this activity. Make a hypothesis about any notable difference.

Answer 1

The interpolated velocity value from the graph is -8.1 meters/second. The calculated value based on the average acceleration is -8.2 meters/second. This is very good agreement.

Step-by-step explanation:

Answer 2

-3.5

Step-by-step explanation:

b/c the distance is moving in to two A And B A +B or S1 +S2 that is it