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How much force is required to pull a spring 3.0 cm from its equilibrium position if the spring constant is 20 N/m?

1 Answer

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  • Distance=3cm=0.03m
  • Spring constant=k=20N/m
  • Force=F


\\ \rm\rightarrowtail F=-kx


\\ \rm\rightarrowtail F=-20(0.03)


\\ \rm\rightarrowtail F=-0.6N

User Arian Motamedi
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