123k views
0 votes
Here is the question

Here is the question-example-1
User Dan Frade
by
5.1k points

1 Answer

5 votes

Explanation:

the bounded region is from (0,0) to (1,1)

since the cross sections of the solid is perpendicular to the x axis and are square

so cross section area is (x-x2 )^2

so V=integral from 0-1(x-x^2)^2dx

v=integral (x^2-2x^3+x^4)dx

v=1/3x^3-1/2x^4+1/5x^5]01

v=1/3-1/2+15=1/30 unit^3

User Toji
by
4.9k points