Question

1. In Figure 5.9 below ABCD is a parallelogram with m(<ABC) = 43º. A line through A meets CD at E and m(<AED) = 68° Find . a. m(<ADE) b. m(< DAE) c. m(BCD). please the real answer​

Answer 1

M<ADE=M<ABC =43°(PARALLELOGRAM DIAGONALLY EQUAL.

M<DAE=180°-43°-68°

=69°(THE SUM OF INTERNAL ANGLES OF THE TRIANGLE IS 180°.

M<BCD=180°-M<ABC=137°