Question

An object in simple harmonic motion obeys the following position versus time equation: y = (0.50 m) sin (π/2 t). What is the amplitude of vibration and its period of vibration?

Answer 1

Hi there!

The Amplitude is the 'A' value of the following SHM equation:

`x(t) = Asin(\omega t)`

Thus, the amplitude of this object:

A = 0.50 m

The period of vibration is equivalent to:

`T = (2\pi)/(\omega)`

In this instance:

`\omega = (\pi)/(2)`

Therefore:

`T = (2\pi)/((\pi)/(2)) = (4\pi)/(\pi) = \boxed{\text{ 4 seconds.}}`