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A man is 32 years older than his son ten year ago he was three times as old as his son was then find the present age of each?
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A man is 32 years older than his son ten year ago he was three times as old as his son was then find the present age of each?

User RahulKumarShaw
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1 Answer

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x-32=y

x-10=3(y-10)=3y-30

X+20=3y

3x-96=3y

Thus, X+20=3x-96, and 2x=116, X=58

Now, 58–32=y, thus, y=26
User Kubusz
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