Due Tomorrow: Answer question 18 using steps

asked Mar 21, 2022 1.7k views

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$\\ \sf\longmapsto tan51=(BC)/(AB)$

$\\ \sf\longmapsto 1.23=(9)/(AB)$

$\\ \sf\longmapsto AB=(9)/(1.23)$

$\\ \sf\longmapsto AB=7.3\approx 7in$

Now

$\\ \sf\longmapsto AC^2=7^2+9^2$

$\\ \sf\longmapsto AC^2=49+81$

$\\ \sf\longmapsto AC^2=130$

$\\ \sf\longmapsto AC^2\approx 11in$

Shehan Simen answered Mar 27, 2022

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