Question

What is the density of a bowling ball with a mass of 3.0 kg and a volume of 0.0050 m 3 ?

0.002 kg/m 3
0.015 kg/m 3
500 kg/m 3
600 kg/m 3

Answer 1

`\boxed {\boxed {\sf 600 \ kg/m^3}}`

Step-by-step explanation:

We are asked to find the density of a bowling ball. The density of an object is its mass per unit volume. It is calculated by dividing the mass by the volume.

`\rho= (m)/(v)`

The mass of the bowling ball is 3.0 kilograms and the volume is 0.0050 cubic meters.

• m= 3.0 kg
• v= 0.0050 m³

Substitute the values into the formula.

`\rho= (3.0 \ kg)/(0.0050 \ m^3)`

Divide.

`\rho= 600 \ kg/m^3`

The density of the bowling ball is 600 kilograms per cubic meter.

Answer 2

600 kg/m³

Step-by-step explanation:

Formula to use

d = m/v

[] d is the density

[] m is the mass

[] v is the volume

Solving

[Formula] d = m/v

[Plug-in] d = 3/0.0050

[Divide] d = 600 kg/m³

Answer

0.002 kg/m³

0.015 kg/m³

500 kg/m³

600 kg/m³

Have a nice day!

I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather