Explanation:
This is point-slope form:
![y-y1=m(x-x1)](https://img.qammunity.org/2022/formulas/mathematics/college/yxd3xcnqjy06ycw1uth05wnatrssnzmam4.png)
in this case:
![y-3=-(2)/(3) (x+6)](https://img.qammunity.org/2022/formulas/mathematics/college/3jrtz2fzkg8ai6cruser375sby2h37lxlc.png)
Looking at the structure of point slope form up top, you can find the slope and one point.
![m=-(2)/(3) \\x1=-6\\y1=3\\(-6,3)](https://img.qammunity.org/2022/formulas/mathematics/college/t654ncggx3jg6b7xps31z4h8k2k85a36sv.png)
Now, just find the graph with a slope of
that passes through (-6, 3). It's hard to see on the image, but that looks like the top left.
By the way, what's the "no links" thing about? I just came back to this site after a year away