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7. A taxi is travelling at 15 m/s. Its driver accelerates with acceleration 3 m/s2 for 4 s. What is its new velocity​

User Grekkq
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2 Answers

1 vote

Answer:


\boxed {\boxed {\sf 27 \ m/s}}

Step-by-step explanation:

We are asked to find the new or final velocity of a taxi.

We will use the following kinematic equation:


v_f=v_i+at

The car was initially traveling at 15 meters per second. It accelerated at 3 meters per second squared for 4 seconds.


  • v_i=15 m/s

  • a=3 m/s ²
  • t= 4 s

Substitute the values into the formula.


v_f= 15 \ m/s + (3 \ m/s^2* 4 \ s)

Multiply the numbers in parentheses.

  • 3 m/s/s * 4 s = 3 m/s *4 = 12 m/s


v_f= 15 \ m/s +12 \ m/s

Add.


v_f=27 \ m/s

The new velocity of the taxi is 27 meters per second.

User Zin Yosrim
by
4.3k points
3 votes

Hi there!

To solve, we can use the following equation:

vf = vi + at

vi = initial velocity (m/s)

a = acceleration (m/s²)

t = time (s)

vf = final velocity (m/s)

Plug in the given values:

vf = 15 + 3(4)

vf = 15 + 12 = 27 m/s

User SRobertJames
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3.9k points