Question

7. A taxi is travelling at 15 m/s. Its driver accelerates with acceleration 3 m/s2 for 4 s. What is its new velocity​

Answer 1

`\boxed {\boxed {\sf 27 \ m/s}}`

Step-by-step explanation:

We are asked to find the new or final velocity of a taxi.

We will use the following kinematic equation:

`v_f=v_i+at`

The car was initially traveling at 15 meters per second. It accelerated at 3 meters per second squared for 4 seconds.

• 
  `v_i=`15 m/s
• 
  `a=`3 m/s ²
• t= 4 s

Substitute the values into the formula.

`v_f= 15 \ m/s + (3 \ m/s^2* 4 \ s)`

Multiply the numbers in parentheses.

• 3 m/s/s * 4 s = 3 m/s *4 = 12 m/s

`v_f= 15 \ m/s +12 \ m/s`

Add.

`v_f=27 \ m/s`

The new velocity of the taxi is 27 meters per second.

Answer 2

Hi there!

To solve, we can use the following equation:

vf = vi + at

vi = initial velocity (m/s)

a = acceleration (m/s²)

t = time (s)

vf = final velocity (m/s)

Plug in the given values:

vf = 15 + 3(4)

vf = 15 + 12 = 27 m/s