Question

A runner joys 12km north than turs and runs 16km east in three hours.

a. what is his displacement
b. calculate his average speed
c. calculate his average including the direction ​

Answer 1

Step-by-step explanation:

a.displacement is vector quantity there fore

we combine the two direction

`{c}^(2) = \sqrt{ {a}^(2) + {b}^(2) }`

`{c}^(2 ) = \sqrt{ {12}^(2) + {16}^(2) }`

`{c}^(2) = √(400 )`

`c = 20`

displacement is 20km to wards north

b:average speed

`v = s / t`

20/3=6.67

c: please type correctly