Question

Find the 6th term of the geometric sequence whose common ratio is

1/3
and whose first term is 5.

Answer 1

Explanation:

geometric sequence means every new term is created by multiplying the previous term by a certain constant (here 1/3).

s1 = 5

s2 = s1 × 1/3 = 5 × 1/3

s3 = s2 × 1/3 = s1 × 1/3 × 1/3 = 5 × 1/9

sn = sn-1 × 1/3 = s1 × (1/3)^(n-1) = 5 × (1/3)^(n-1)

s6 = 5 × (1/3)⁵ = 5 × 1/243 = 5/243