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Given: F(x)=3 x^2 + 1, G(x)= 2 x-3 , H(x)=x
F(G(x))=

1 Answer

3 votes

Answer:

f(g(x)) = 12x² - 36x + 28

Explanation:

Substitute x = g(x) into f(x) , that is

f(g(x) )

= f(2x - 3)

= 3(2x - 3)² + 1 ← expand factor using FOIL

= 3(4x² - 12x + 9) + 1 ← distribute parenthesis by 3

= 12x² - 36x + 27 + 1 ← collect like terms

= 12x² - 36x + 28

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