Question

Please help me figure out how to solve the problem below:

the problem below is asking how to find the surface area of the cylinder. please leave an explanation on how to solve it.

formula: 2(3.14)(r)^2 + 2(3.14)(r)
r: radius ​

Answer 1

3315.84mm^2.

Explanation:

We calculate the diameter of the base of the cylinder using Pythagoras:

40^2 = d^2 + 32^2

d^2 = 40^2 - 32^2 = 576

d = sqrt 576 = 24 mm.

So the radius = 1/2 diameter = 12 mm.

The surface area

= 2(3.14)(12)^2 + 2(3.14)(12)(32)

= 904.32 + 2411.52

= 3315.84.