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User Ashlocke
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Answer:

(c) -0.9682

Explanation:

In quadrant II, the cosine is negative. Solving the given equation for the cosine gives ...

sin²(A) +cos²(A) = 1

cos²(A) = 1 -sin²(A)

cos(A) = -√(1 -sin²(A)) = -√(1 -(1/4)²) = -√(15/16) ≈ -0.9682

_____

The coordinates of a point on the unit circle are (cos(α), sin(α)). The attachment shows the point on the unit circle where sin(A)=1/4 in quadrant II. The x-coordinate is the cosine of the angle, about -0.97.

Can someone help me please. I’ll give you ratings-example-1
User Yeah Its Me
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