Question

What are the roots of the equation 16x² + 16x + 5 = 0 in simplest a + bi form?​

Answer 1

Below in bold.

Explanation:

Using the quadratic formula :

roots = [-16 +/-√(16^2 - 4*16*5)] / (2*16)

= -0.5 +/- √(-64) /32

= -0.5 +/- 8i/32

= -0.5 + 0.25i and -0.5 - 0.25i

Answer 2

`\sf\longmapsto 16x^2+16x+5=0`

`\sf\longmapsto x=(-b\pm√(b^2-4ac))/(2a)`

`\sf\longmapsto x=(-16\pm√(16^2-4(16)(5)))/(2(16))`

`\sf\longmapsto x=(-16\pm√256-320)/(32)`

`\sf\longmapsto x=(-16\pm√-64)/(32)`

`\sf\longmapsto x=(-16\pm8i)/(32)`

`\sf\longmapsto x=(-2\pm i)/(4)`

`\sf\longmapsto x=(-1)/(2)\pm(1)/(4)i`