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The factorization of 12a^2b+15ab^2 gives:

1 point
3ab(4a+5b)
3b(4a + 5b)
3a(4a+5b)
3ab(4ab+5)
The factorization of 12x+36 is
1 point
12(x+3)
12(3x)
12(3x+1)
x(12+36x)
On factorising 14pq + 35pqr, we get:
1 point
pq(14+35r)
p(14q+35qr)
7pq(2+5r)
q(14p+35pr)
The factors of x^2 +xy+8x+8y are:
1 point
(x+y) (x+8)
(x+2y) (x+8)
(2x+y) (x+8)
(x+y) (2x+8)
Which of the following are the factors of a^2 + ab +bc + ca
1 point
(b + c) (c + a)
(a + b) (a + c)
a(a + b + c)
(a + b) (b + c).
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1 Answer

2 votes

Answer:

Explanation:

3ab (4a+5b)

12 (x+3)

7pq (2+5r)

(x+y)(x+8)

User Brian Wright
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