5.0k views
17 votes
Trigonometry, how would I find the area of this triangle?

Trigonometry, how would I find the area of this triangle?-example-1

2 Answers

6 votes

Use sine rule for Area


\\ \rm\rightarrowtail Area=(1)/(2)absinC


\\ \rm\rightarrowtail Area=(1)/(2)(3.9)(5.6)sin56°45'


\\ \rm\rightarrowtail Area=10.92(0.836)


\\ \rm\rightarrowtail Area=10.22cm^2

User Oklahomer
by
8.5k points
7 votes

Answer:

Explanation:

Area of triangle = 1/2 * base * height

Use the side of length 5.6cm as base, the height will be a perpendicular line from the base to the tip of the triangle.

From the right-angle triangle formed by the height and the side of length 3.9cm,

sin(56°45') = height / 3.9

height = 3.9*sin(56°45')

Substituting back into the area equation:

Area = 1/2*5.6*3.9*sin(56°45')

= 9.0cm^2

= 9cm^2

User Engel
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories