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(c - b * cos A)/(b - c * cos A) = (cos B)/(cos C)​
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(c - b * cos A)/(b - c * cos A) = (cos B)/(cos C)​

User Rafahoro
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1 Answer

1 vote

Answer:

a

Explanation:

User Ivan Kvyatkovskiy
by
6.1k points
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