Question

Find the last digit of 17 to the power 17

Answer 1

We know that the cyclicity power (a^n) of 17 is 4.

• Divide 4 then replace to a new number
• The number is as follows:-
• The number is a remainder.

`\sf \longmapsto\bigg( (17)/(4)\bigg) = 1`

• Solving Further

`\sf \longmapsto17^((17/4))`

`\sf \longmapsto17 {}^{}`

`\sf \longmapsto7(last \: digit )`