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What are the states of matter for the following equation?

6Br⁻ + XeO₃ + 6H⁺ → 3Br₂ + Xe + 3H₂O

User Wig
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Answer:

Step-by-step explanation:

On the reactant side, XeO3 is a strong oxidizing agent. It can be a solid or gas. Most likely it is in a solid state.

H+ and Br- combine to form HBr which is a weak acid. So H+ and Br- are in an aqueous state.

On the product side, both Br2 and Xe are not very soluble in water. They will be in gaseous state and H2O is water i.e. liquid state.

User Izikon
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