Answer:
B 13/2
Explanation:
2x² + 7x - 15 = 0
First we want to find the two solutions
We can do this by using the quadratic formula
Quadratic formula:

Where the values of a,b and c are derived from the equation.
The equation is put in ax² + bx + c = 0 form
2x² + 7x - 15 = 0
so a = 2, b = 7 and c = - 15
We now plug these values into the quadratic formula
(-(7) + or - √7² - 4(2)(-15) ) / 2(2)
first solution: -(7) + √7² - 4(2)(-15) ) / 2(2)
remove parenthesis on 7
(-7 + √7² - 4(2)(-15) ) /2(2)
Apply exponents 7²
(-7 + √49 - 4(2)(-15) ) /2(2)
Multiply -4,2 and -15
(-7 + √49 + 120 ) / 2(2)
add 49 and 120
(-7 + √ 169 ) / 2(2)
Take square root of 169
(-7 + 13 ) / 2(2)
add 13 and -7
6/2(2)
multiply 2 and 2
= 6/4
The first solution is 6/4 or 1.5
Now the second solution: -(7) - √7² - 4(2)(-15) ) / 2(2)
For the second solution we basically go through the same steps as for finding the first solution, the only difference is instead of adding -b and √b² - 4(a)(c) we are subtracting.
So we would have ( -7 - 13 ) / 2(2) instead of (-7+13)/2(2)
So second solution: ( -7 - 13 ) / 2(2)
subtract 13 from -7
-20/2(2)
multiply 2 and 2
-20/4
divide
The second solution is -5
Now that we have found the solutions we want to find r - s if r and s are the solutions to the equation and that r > s
The two solutions are 6/4 and -5.
6/4 > -5 so we know that r must equal 6/4 and s must equal -5 because r has to be greater than s
So if r = 6/4 and s = -5
Then r - s = 6/4 - (-5) = 6/4 + 5 = 13/2
So the answer is B. 13/2