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Write the equation of the circle centered at (10, – 4) that passes through (14, 12).

User Daiana
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1 Answer

5 votes

Answer:

(x -10)² +(y +4)² = 272

Explanation:

The equation of a circle with center (h, k) and radius r is ...

(x -h)² +(y -k)² = r²

The center is given as (h, k) = (10, -4). We can find the value of r² using the "passes through" point coordinates:

(14 -10)² +(12 -(-4))² = r² = 16 +256 = 272

Then for the given center and the value of r² we found, the equation is ...

(x -10)² +(y +4)² = 272

Write the equation of the circle centered at (10, – 4) that passes through (14, 12).-example-1
User Renathy
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