Question:
How to find g (acceleration due to gravity)
Solution:
We know,
Acceleration due to gravity (g)
![= \frac{GM}{ {R}^(2) }](https://img.qammunity.org/2022/formulas/physics/college/2qr7iesc1j40fsfrbkgt7oe6comwm6xy2q.png)
where, G = Gravitational constant
![= 6.67 * {10}^(11) N {m}^(2)/k {g}^(2) \\](https://img.qammunity.org/2022/formulas/physics/college/ui69g2aecc243nb3i7bdty68hdgxcn63gy.png)
M = Mass of the earth
![= 6 * {10}^(24) \: kg](https://img.qammunity.org/2022/formulas/physics/college/6160lkfn0hb0enlkml61pq8x7xtjsr6c2o.png)
R = Radius of the earth
![= 6.4 * {10}^(6) m](https://img.qammunity.org/2022/formulas/physics/college/44sbx8fbgiq68j5jfgf251he5dfxxfw1sb.png)
Putting these values of G, M and R in the above formula, we get
![g \: = \: \frac{6.67 * {10}^(11) N {m}^(2)/k {g}^(2) * \: 6 * {10}^(24) \: kg }{(6.4 * {10}^(6)m {)}^(2) } \\ = 9.8m/ {s}^(2)](https://img.qammunity.org/2022/formulas/physics/college/9fcg40bmkg0km5v06hfia1n9is7xqonhxc.png)
So, the value of acceleration due to gravity is
![9.8m/s ^(2)](https://img.qammunity.org/2022/formulas/physics/college/9uzx6isikgzzrdswot5z2ndstbm5md8wvg.png)
Hope it helps.
Do comment if you have any query.