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PLEASE HELP ME !!!

The average of 5 consecutive even integers is 6. What is the least of these 5 integers?

User DoodleKana
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1 Answer

2 votes

Answer: 2

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Step-by-step explanation:

Let x be the smallest even integer. The next one up is x+2. Then after that is (x+2)+2 = x+4, etc. Each time we need the next even integer, we add on 2.

We have this list:

  • x = first
  • x+2 = second
  • x+4 = third
  • x+6 = fourth
  • x+8 = fifth

We'll add up those expressions to get

(x)+(x+2)+(x+4)+(x+6)+(x+8)

(x+x+x+x+x)+(2+4+6+8)

5x+20

Then we divide that over 5 since we want to find the average. Set that result equal to the desired average of 6 and solve for x.

(5x+20)/5 = 6

5x+20 = 5*6

5x+20 = 30

5x = 30-20

5x = 10

x = 10/5

x = 2 is the smallest number in the list

The rest of the list is:

  • x+2 = 2+2 = 4
  • x+4 = 2+4 = 6
  • x+6 = 2+6 = 8
  • x+8 = 2+8 = 10

The full list being: {2,4,6,8,10}

Adding up everything in the list gets us: 2+4+6+8+10 = 30

Divide that over five to find the average: 30/5 = 6

We get the proper arithmetic mean, so this confirms the correct answer.

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Here's another approach:

Start with the average 6. This is the center of the list of five values. Because it's the center, we spread out by going 2 units up and 2 units down from this center. So we'll go from {6} to {4,6,8}. This expansion process is then applied again to go from {4,6,8} to {2,4,6,8,10}. At this point, we can see there are five values here and the center is definitely 6. More importantly, the smallest item here is 2

User Tobrun
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