Solve the equations. \sqrt{x^(2) } =14 \sqrt{x^(2) } =17 \sqrt{y^(2) } =5

Question

Solve the equations.


`\sqrt{x^(2) } =14`

`\sqrt{x^(2) } =17`

`\sqrt{y^(2) } =5`

Answer 1

`x=\pm14\\x=\pm17\\y=\pm5`

Explanation:

Generally, equations in the form
`√(x^2)=c` where
`c` is some constant, would have
`x=\pm c` as its solution.

This is because the square of a number is always positive regardless of the sign of
`x`.